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A step pulley system is shown in figure-...

A step pulley system is shown in figure-2.50. Find the relation in masses m and M for which the system remain in equilibrium. Assume string will not slide over the pulleys. `((r_(1))/(r_(2))=(1)/(2),(r_(3))/(r_(4))=(3)/(4))`

`[(M)/(m)=(3)/(8)sintheta]`

Answer

Step by step text solution for A step pulley system is shown in figure-2.50. Find the relation in masses m and M for which the system remain in equilibrium. Assume string will not slide over the pulleys. ((r_(1))/(r_(2))=(1)/(2),(r_(3))/(r_(4))=(3)/(4)) [(M)/(m)=(3)/(8)sintheta] by PHYSICS experts to help you in doubts & scoring excellent marks in Class 11 exams.

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Knowledge Check

  • In the pulley system shown here, find the relationship between acceleration of m_(1),m_(2) and m_(3)

    A
    `2a_(1)+a_(3)+a_(1)=0`
    B
    `2a_(2)-a_(3)+a_(1)=0`
    C
    `2a_(2)+a_(3)-a_(1)=0`
    D
    `2a_(2)-a_(3)-a_(1)=0`

  • All surfaces shown in figure are smooth. For what ratio m_(1): m_(2):m_(2):m_(3) , system is in equilibrium. All pulleys and strings are massless.

    A
    `1:2:1`
    B
    `2:2:1`
    C
    `2:1:2`
    D
    `1:2:3`

  • Two masses m and M are attached to the strings as shown in the figure. If the system is in equilibrium, then

    A
    `tantheta=1+(2M)/(m)`
    B
    `tantheta=1+(2m)/(M)`
    C
    `cottheta=1+(2M)/(m)`
    D
    `cottheta=1+(2m)/(M)`

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