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Two masses M and m are connect by a ligh...

Two masses M and m are connect by a light string gong over a pulley of radis r. The pulley is free to rotate about its axis which is kept horizontal. The moment of inertia of the pulley about the axis is I. The system is releaed from rest. Find the angular momentum fo teh system when teh mass Mhas descended through a height h. The string does not slip over the pulley.

Text Solution

Verified by Experts

The correct Answer is:
`"["sqrt([2(M-m){M+m+(1)/(r^(2))}r^(2)gh]"]"`
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Knowledge Check

  • Two masses M and m(M gt m) are joined by a light string passing over a smooth light pulley.

    A
    The acceleration of each block is `((M-m)/(M+m))g`
    B
    The tension in the string is `(2Mmg)/(M+m)`
    C
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    D
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  • Two masses m and M(m lt M) are joined by a light string passing over a smooth and light pulley (as shown)

    A
    the acceleration of each mass is `((M-m)/(M+m))g`
    B
    the tension in the string connecting masses is `((2Mm)/(M+m))g`
    C
    the thrust acting on the pulley is `((4Mm)/(M+m))g`
    D
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    A
    `g((M-m)/(M+m))" downward"`
    B
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    C
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    D
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