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Two bodies of masses 1kg and 2kg are lyi...

Two bodies of masses 1kg and 2kg are lying in xy plane at (-1,2) and (2,4) respectively. What are the coordinates of the center of mass?

A

(1,10/3)

B

(1,0)

C

(0,1)

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the coordinates of the center of mass (CM) of two bodies with given masses and positions, we can follow these steps: ### Step 1: Identify the masses and their positions - Mass \( m_1 = 1 \, \text{kg} \) is located at point \( A(-1, 2) \). - Mass \( m_2 = 2 \, \text{kg} \) is located at point \( B(2, 4) \). ### Step 2: Write down the formula for the center of mass The coordinates of the center of mass \( (x_{cm}, y_{cm}) \) can be calculated using the formula: \[ x_{cm} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2} \] \[ y_{cm} = \frac{m_1 y_1 + m_2 y_2}{m_1 + m_2} \] where \( (x_1, y_1) \) and \( (x_2, y_2) \) are the coordinates of the two masses. ### Step 3: Substitute the values into the formula - For the x-coordinate: \[ x_{cm} = \frac{1 \cdot (-1) + 2 \cdot 2}{1 + 2} = \frac{-1 + 4}{3} = \frac{3}{3} = 1 \] - For the y-coordinate: \[ y_{cm} = \frac{1 \cdot 2 + 2 \cdot 4}{1 + 2} = \frac{2 + 8}{3} = \frac{10}{3} \] ### Step 4: Combine the results Thus, the coordinates of the center of mass are: \[ (x_{cm}, y_{cm}) = \left(1, \frac{10}{3}\right) \] ### Final Answer The coordinates of the center of mass are \( \left(1, \frac{10}{3}\right) \). ---

To find the coordinates of the center of mass (CM) of two bodies with given masses and positions, we can follow these steps: ### Step 1: Identify the masses and their positions - Mass \( m_1 = 1 \, \text{kg} \) is located at point \( A(-1, 2) \). - Mass \( m_2 = 2 \, \text{kg} \) is located at point \( B(2, 4) \). ### Step 2: Write down the formula for the center of mass The coordinates of the center of mass \( (x_{cm}, y_{cm}) \) can be calculated using the formula: ...
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Knowledge Check

  • Two bodies of masses 5kg and 3kg are moving towards each other with 2ms^(-1) and 4ms^(-1) respectively. Then velocity of centre of mass is

    A
    `0.25 ms^(-1)` towards `3kg`
    B
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    C
    `0.25 ms^(-1)` towards`5 kg`
    D
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  • Two bodies of mass 2 kg and 5 kg have position (1 m, 2 m, 1 m) and (3 m, 2 m, -1 m) respectively. The position vector of centre of mass is

    A
    `(frac{17}{7}hati + 2hatj - frac{3}{7}hatk)m`
    B
    `(17hati + 14hatj - 3hatk)m`
    C
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    D
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    A
    `r_(1):r_(2)`
    B
    `2r_(1):r_(2)`
    C
    `r_(1):2r_(2)`
    D
    `r_(1): r_(2)`
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