Home
Class 11
PHYSICS
A black body is at a temperature of 5760...

A black body is at a temperature of `5760 K`. The energy of radiation emitted by the body at wavelength `250 nm` is `U_(1)` at wavelength `500 nm` is `U_(2)` and that at `1000 nm` is `U_(3)`. Wien's consant, `b = 2.88 xx 10^(6) nmK`. Which of the following is correct?

A

`U_(3)` = 0

B

`U_(1)gtU_(2)`

C

`U_(2)gtU_(1)`

D

`U_(1) = 0`

Text Solution

Verified by Experts

The correct Answer is:
C
c) Given, temperature , `T_(1)=57600K`
Since, it is given that energy of radiation emitted by the body at wavelength 250 nm is `U_(1)`, at wavelength 500nm is `U_(2)` and that at 1000 nm is `U_(3)`.
`therefore`According to Wien's law, we get
`lambda_(m)T`=b
where, b = Wien's constant = `2.88 xx 10^(6)` nmK
`rArr lambda_(m)=b/T` `rArr lambda_(m) = (2.88 xx 10^(6)nmK)/(5760K)rArr lambda_(m)`=500 nm
`therefore lambda_(m)=b/T rArr lambda_(m) = (2.88 xx 10^(6))/(5760K)` `rArr lambda_(m)` = 500 nm
`therefore` `lambda_(m)` = wavelength corresponding to maximum energy, so, `U_(2)gtU_(1)`.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CALORIMETRY AND HEAT TRANSFER

    DC PANDEY|Exercise Match the columns|4 Videos

  • CALORIMETRY & HEAT TRANSFER

    DC PANDEY|Exercise Level 2 Subjective|14 Videos

  • CENTRE OF MASS

    DC PANDEY|Exercise Medical entrances gallery|27 Videos

Similar Questions

Explore conceptually related problems

A black body is at a temperature of 2880 K. The energy of radiation emitted by this object with wavelength between 499 nm and 500 nm is U_(1) , between 999 nm and 1000 nm is U_(2) and between 1499 nm and 1500 nm is U_(3) . The Wein's constant b = 2.88 xx 10^(6) "nm K" . Then

A black body is at a temperature of 2880 K. The energy of radiation emitted by this object with wavelength between 4990 A and 5000A is E_(1) , and that between 9990 A and 10000 A is E_(2) . Find the ratio of E_(2) and E_(1) .

Knowledge Check

  • A black body is at a temperature of 5760 K. The energy of radiation emitted by the body at wavelength 250 nm is U_(1) , at wavelength 500 nm is U_(2) and at 1000 nm is U_(3) , Wien's constant, b=2.88xx10^(6) nm K, which of the following is correct ?

    A
    `U_(1)=0`
    B
    `U_(3)=0`
    C
    `U_(1)gtU_(2)`
    D
    `U_(2)gtU_(1)`

  • The energy of radiation emitted by the wavelength 250 nm is U_(1) , at wavelength 500 nm is U_(2) and that at 1000 nm is U_(3) . Wien's law b=2.88xx10^(6) nmK. Which of the following is :

    A
    `U_(1)=0`
    B
    `U_(3)=0`
    C
    `U_(1)gtU_(2)`
    D
    `U_(2)gtU_(1)`

  • A black body is at a temperature of 2800K The energy of radiation emitted by this object with wavelength between 499nm and 500 nm is U_(1) between 999nm and 1000nm is U_(2) and between 1499 nm and 1500 nm is U_(3) The Wien's constant b =2.80 xx 10^(6) nm K Then .

    A
    `U_(1)=0`
    B
    `U_(3)=0`
    C
    `U_(1)gtU_(2)`
    D
    `U_(2)gtU_(1)`

    • Similar Questions

    Explore conceptually related problems

    A blackbody is at a temperature of 2880K. The energy of radiation emitted by this object with wavelength between 499nm and 500nm is U_1 , between 999nm and 1000nm is U_2 and between 1499 nm and 1500 nm is U_3 . The Wien constant b=2.88xx10^6nmK . Then

    A black body is at a temperature of 2880 K. The density of radiation emitted by this body with wavelength between 499 nm and 500 nm is U_(1) , between 999 nm and 1000 nm, is U_(2) and between 1499 nm and 1500 nm nm is U_(3) . Whose constant, b=2.88xx10^(6) nm - K, then,

    Compare the energies of two radiations E_(1) with wavelength 800 nm and E_(2) with wavelength 400 nm.

    The radiation emitted by a black body at a temperature of 2618 K with the wavelength between 599 nm and 600 nm is U_a , between 1099 nm and 1100 nm is _b U and between 1599 nm and 1600 nm is U_c . If the Wien's constant is b = 2.88 xx 10^6 nm K then,

    The effective area of a black body is 0.1 m^2 and its temperature is 1000 K . The amount of radiations emitted by it per min is –

    Home
    Profile