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A particle of mass m, collides with anot...

A particle of mass m, collides with another stationary particle of mass M. If the particle m stops just after collision, then the coefficient of restitution for collision is equal to

A

1

B

`m/M`

C

`(M-m)/(M+m)`

D

`m/(M+m)`

Text Solution

Verified by Experts

The correct Answer is:
B

As net horizontal force acting on the system is zero, hence, momentum must remain conserved.
Hence, `mu + 0 = 0 +Mv_(2)`
As per definition, `e = |(v_(2)-v_(1))|/|(u_(2)-u_(1))| = |(v_(2)-0)/(0-u)|`
`v_(2)/u= (mu)/(M)/u = m/M`
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Knowledge Check

  • A particle of mass m collides with another stationary particle of mass M such that the second particle starts moving and the first particle stops just after the collision. Then which of the following conditions must always be valid ?

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    A
    `m_(1)` will retrun back
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    `m_(1)` will move in same direction
    C
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    D
    unpredictable
  • A particle (A) of mass m_(1) elastically collides with another stationary particle (B) of mass m_(2) . Then :

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    C
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