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Bromine in excess is dropped to a 0.01 M...

Bromine in excess is dropped to a 0.01 M `SO_(2)`. All of `SO_(2)` is oxidized to `H_(2)SO_(4)` and the excess `Br_(2)` is removed by flushing with gaseous `N_(2)`. Determine the pH of the resulting solution assuming `K_(a1)` of `H_(2)SO_(4)` vary large & `K_(a2) = 10^(-2)`. Take the value of `log (3.24) = 0.51`.

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The correct Answer is:
1.49
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