Home
Class 11
CHEMISTRY
The correct order for melting point and ...

The correct order for melting point and boiling point of IV group hydrides respectively
I) `CH_(4) lt SiH_(4) lt GeH_(4) lt SnH_(4)`
II) `CH_(4) gt SiH_(4) lt GeH_(4) lt SnH_(4)`
III) `SnH_(4) lt GeH_(4) lt SiH_(4) lt CH_(4)`
IV) `CH_(4) lt SiH_(4) gt GeH_(4) gt SnH_(4)`

A

II,I

B

I,II

C

III, IV

D

IV, III

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct order for the melting point and boiling point of Group IV hydrides (CH₄, SiH₄, GeH₄, SnH₄), we need to analyze the factors affecting these properties. ### Step-by-Step Solution: 1. **Identify the Hydrides**: The hydrides we are considering are: - Methane (CH₄) - Silane (SiH₄) - Germanium hydride (GeH₄) - Stannane (SnH₄) 2. **Understand the Trends**: - As we move down the group from carbon to lead, the molecular mass of the hydrides increases. - The boiling and melting points are influenced by the strength of intermolecular forces, which are primarily Van der Waals forces in these hydrides. 3. **Evaluate Molecular Mass**: - CH₄ has the lowest molecular mass. - SiH₄ has a higher molecular mass than CH₄. - GeH₄ has a higher molecular mass than SiH₄. - SnH₄ has the highest molecular mass among these hydrides. 4. **Assess Intermolecular Forces**: - Van der Waals forces increase with increasing molecular mass. - Therefore, SnH₄, having the highest molecular mass, will have the strongest intermolecular forces, leading to the highest boiling and melting points. 5. **Determine the Order**: - For boiling points: The order will be SnH₄ > GeH₄ > SiH₄ > CH₄. - For melting points: The order will be similar, but CH₄ will have the lowest melting point due to its tetrahedral structure allowing it to be more easily melted. 6. **Check the Options**: - I) `CH₄ < SiH₄ < GeH₄ < SnH₄` (This is incorrect for boiling points) - II) `CH₄ > SiH₄ < GeH₄ < SnH₄` (This is incorrect for both) - III) `SnH₄ < GeH₄ < SiH₄ < CH₄` (This is incorrect) - IV) `CH₄ < SiH₄ > GeH₄ > SnH₄` (This is incorrect) 7. **Conclusion**: - The correct order for boiling points is SnH₄ > GeH₄ > SiH₄ > CH₄. - The correct order for melting points is also SnH₄ > GeH₄ > SiH₄ > CH₄, but CH₄ has the lowest melting point. ### Final Answer: None of the provided options correctly represent the order for both melting and boiling points of Group IV hydrides.
Promotional Banner

Topper's Solved these Questions

  • 14TH GROUP ELEMENTS

    NARAYNA|Exercise Level-IV|9 Videos
  • 14TH GROUP ELEMENTS

    NARAYNA|Exercise Matrix Matching Type|14 Videos
  • 14TH GROUP ELEMENTS

    NARAYNA|Exercise Level-II (C.W)|17 Videos
  • 13TH GROUP ELEMENTS

    NARAYNA|Exercise Comphensive Type Question|22 Videos
  • ACIDS & BASES

    NARAYNA|Exercise EXERCISE-III|43 Videos

Similar Questions

Explore conceptually related problems

Which among CH_(4), SiH_(4), GeH_(4) , and SnH_(4) is the most volatile?

The correct sequence of bond enthalpy of 'C-X' bond is : (1) CH_(3)-F gt CH_(3)-Cl gt CH_(3)-Br gt CH_(3)-I (2) CH_(3)-F lt CH_(3)-Cl gt CH_(3)-Br gt CH_(3)-I (3) CH_(3)-Cl gt CH_(3)-F gt CH_(3)-Br gt CH_(3)-I (4) CH_(3)-F lt CH_(3)-Cl lt CH_(3)-Br lt CH_(3)-I

The difference in properties of CH_(4) and SiH_(4) is due to :

Which is the correct sequence in the following properties. For the correct order mark ( T) and for the incorrect order mark ( F) : {:((a)"Acidity order ":SiF_(4) lt SiCl_(4) lt SiBr_(4) lt Sil,,(b)"Melting point":NH_(3) gt SbH_(3) gt AsH_(3) gt PH_(3),,),((c )"Boiling point " :NH_(3) gt SbH_(3) gt AsH_(3) gt PH_(3),,(d)"Dipole moment order ":NH_(3) gt SbH_(3) gt AsH_(3) gt PH_(3),=,5):}

The correct code for stability, of oxidation states for given cations is: (i) Pb^(2+) gt Pb^(4+) ,Tl^(+) lt Tl^(3+) (ii) Bi^(3+) lt Sb^(3+) , Sn^(3+) lt Sn^(4+) (iii) Pb^(3+) gt Pb^(4+),Bi^(3+) gt Bi^(3+) (iv) Tl^(3+) lt ln^(3+), Sn^(2+) gt Sn^(4+) (v) Sn^(2+) lt Pb^(2+) , Sn^(4+) gt Pb^(4+) (vi) Sn^(2+) lt Pb^(2+), Sn^(4+) lt Pb^(4+)

The ionization potential values of an element are in the following order I_(1) lt I_(2) lt lt lt lt I_(3) lt I_(4) lt I_(5) . The element is

Consider the hydrides of group 14 elements 1. CH_4 2. SiH_4 3. GeH_4 4. SnH_4 The correct sequence of thermal stability is

NARAYNA-14TH GROUP ELEMENTS-Level-III
  1. The correct order for melting point and boiling point of IV group hydr...

    Text Solution

    |

  2. The order of the stability of dihalides of Si, Ge, Sn and Pb changes i...

    Text Solution

    |

  3. A metal, M from chaloride in its +2 and +4 oxidation states . Which of...

    Text Solution

    |

  4. Graphite is a soft solid lubricant extremely difficult to melt. The re...

    Text Solution

    |

  5. L(1) is the length between two adjacent carbon atoms in a layer and L(...

    Text Solution

    |

  6. Which of the following statement is wrong about CO

    Text Solution

    |

  7. The reaction that gives CO(2) as one of the products is

    Text Solution

    |

  8. Carbon dioxide is a gas but silica is a solid because

    Text Solution

    |

  9. The tetravalent elements A and B form dioxides both react with NaOH to...

    Text Solution

    |

  10. SiO(2) + A to X + Y. In this reaction 'Y' is one of the global warming...

    Text Solution

    |

  11. Silica reacts with hydride of superhalogen to form 'X'. On hydrolysis ...

    Text Solution

    |

  12. Oftern aground glass stropper gets stuck in the neck of a glass bottle...

    Text Solution

    |

  13. Identify B in the following H(4)SiO(4) underset(-H(2)O) overset(1000^(...

    Text Solution

    |

  14. An alkyl halide reacts with a group 14 element, 'Y' at 570 K with Cu a...

    Text Solution

    |

  15. Which of the following exists as covalent crystals in the solid state?

    Text Solution

    |

  16. The soldiers of Napoleon army while at Alps during freezing winter suf...

    Text Solution

    |

  17. Among the following substituted silanes, the one which will give rise ...

    Text Solution

    |