Home
Class 11
CHEMISTRY
In HS^(-), I^(-), R-NH(2), NH(3) order o...

In `HS^(-)`, `I^(-)`, `R-NH_(2)`, `NH_(3)` order of proton accepting tendency will be

A

`I^(-)gtNH_(3)gtRNH_(2)gtHS^(-)`

B

`NH_(3)gtRNH_(2)gtHS^(-)gtI^(-)`

C

`RNH_(2)gt NH_(3)gtHS^(-)gtI^(-)`

D

`HS-gtRNH_(2)gtNH_(3)gtI^(-)`

Text Solution

Verified by Experts

The correct Answer is:
C
`RNH_(2)` is a stronger base then `NH_(3)`. Also HI is a strong acid and thus `I^(-)` is a weak base
Promotional Banner

Topper's Solved these Questions

  • ACIDS & BASES

    NARAYNA|Exercise EXERCISE-II (H.W.) (SOLUBILITY PRODUCT & COMMON ION EFFECT)|18 Videos

  • 14TH GROUP ELEMENTS

    NARAYNA|Exercise Subjective Questions|6 Videos

  • ALKANES

    NARAYNA|Exercise Integer Answer Type|7 Videos

Similar Questions

Explore conceptually related problems

For NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g) , the observed, pressure for reaction mixture in equilibrium is 1.12 atm at 106^(@)C . What is the value of K_(p) for the reaction?

5.1g of solid NH_(4)HS is introduced in a 16.4 lit. vessel & heated upto 500 K K_(B) for equilibrium NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g) is 0.16 . The maximum pressure developed in the vessel will be :

One "mole" of NH_(4)HS(s) was allowed to decompose in a 1-L container at 200^(@)C . It decomposes reversibly to NH_(3)(g) and H_(2)S(g). NH_(3)(g) further undergoes decomposition to form N_(2)(g) and H_(2)(g) . Finally, when equilibrium was set up, the ratio between the number of moles of NH_(3)(g) and H_(2)(g) was found to be 3 . NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g), K_(c)=8.91xx10^(-2) M^(2) 2NH_(3)(g) hArr N_(2)(g)+3H_(2)(g), K_(c)=3xx10^(-4) M^(2) Answer the following: To attain equilibrium, how much % by weight of folid NH_(4)HS got dissociated?

One "mole" of NH_(4)HS(s) was allowed to decompose in a 1-L container at 200^(@)C . It decomposes reversibly to NH_(3)(g) and H_(2)S(g). NH_(3)(g) further undergoes decomposition to form N_(2)(g) and H_(2)(g) . Finally, when equilibrium was set up, the ratio between the number of moles of NH_(3)(g) and H_(2)(g) was found to be 3 . NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g), K_(c)=8.91xx10^(-2) M^(2) 2NH_(3)(g) hArr N_(2)(g)+3H_(2)(g), K_(c)=3xx10^(-4) M^(2) Answer the following: Assuming the volume due to solid NH_(4)HS is negligible what will be the density of the gaseous mixture in the above equilibrium system?

Among (i) C_(6)H_(5) NH_(2) (ii) CH_3NHCH_(3) (iii) (CH_3)_2NCH_(3) and (iv) NH_3 , the correct order of basic strength follows the order

The decomposition of NH_(3) on finely divided platinum follows the rate expression Rate =(k_(1)[NH_(3)])/(1+k_(2)[NH_(3)]) it is a first order reaction when concentration of NH_(3) is

Consider the heterogeneous equilibrium in a closed container NH_(4)HS (s)hArrNH_(3) (g) + H_(2)S(g) If more NH_(4)Hs is added to the equilibrium

Knowledge Check

  • When NH_3 accepts a proton in aqueous solution

    A
    H-N-H bond angle changes from `107^@` to `109.5^@`
    B
    % s-character of the hybrid orbital of N in both `NH_3` and the product remains the same
    C
    both (a) and (b)
    D
    none of the above.

  • Ammonium bydrogen sulfied, NH_(4)HS is unstable at room temperature and decomposes as : NH_(4)HS (s) hArr NH_(3) (g) + H_(2)S (g) Then which of the following will produce less H_(2)S (g) :

    A
    Removing some of `NH_(3)` form flask.
    B
    Removing some of `NH_(4)HS (s)`.
    C
    On increasing pressure by decreasing volume
    D
    Increasing temperature.

  • 5.1g of solid NH_(4)HS is introduced in a 16.4 lit. vessel & heated upto 500 K K_(B) for equilibrium NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g) is 0.16 . The maximum pressure developed in the vessel will be :

    A
    `0.8 atm`
    B
    `0.40 atm`
    C
    `0.5 atm`
    D
    None of these
    • NARAYNA-ACIDS & BASES-EXERCISE-III
    1. In HS^(-), I^(-), R-NH(2), NH(3) order of proton accepting tendency wi...

      Text Solution

      |

    2. NH(3) gas dissolves in water to give NH(4)OH. In this reaction, water ...

      Text Solution

      |

    3. Ionisation constant of CH(3)COOH is 1.7xx10^(-5) and concentration of ...

      Text Solution

      |

    4. Solubility of M(2)S type salt is 3.5xx10^(-3) then find out its solubi...

      Text Solution

      |

    5. Solubility of MX(2) type electrolytes is 0.5xx10^(-4) mol//L, then fin...

      Text Solution

      |

    6. Which has the highest pH?

      Text Solution

      |

    7. Solution of 0.1 N NH(4)OH and 0.1 N NH(4)Cl has pH 9.25, then find out...

      Text Solution

      |

    8. The solubility product of AgI at 25^(@)C is 1.0xx10^(-16) mol^(2) L^(-...

      Text Solution

      |

    9. The rapid change of pH near the stoichiometric point of an acid-base t...

      Text Solution

      |

    10. The solubility product of a sparingly soluble salt AX(2) is 3.2xx10^(-...

      Text Solution

      |

    11. The correct relationship between the pH of isomolar solutions of sodiu...

      Text Solution

      |

    12. At 25^(@)C, the dissociation constant of a base. BOH is 1.0xx10^(-12)...

      Text Solution

      |

    13. H(2)S gas when passed through a solution of cations containing HCl pre...

      Text Solution

      |

    14. Which of the following pairs consitutes buffer?

      Text Solution

      |

    15. The hydrogen ion concentration of a 10^(-8) M HCl aqueous soultion at ...

      Text Solution

      |

    16. Calculate the pOH of solution at 25^(@)C that contains 1xx10^(-10) M o...

      Text Solution

      |

    17. A monoprotic acid in 0.1 M solution has K(a)=1.0xx10^(-5). The degree...

      Text Solution

      |

    18. Equimolar solution of the following were prepared in water separately....

      Text Solution

      |

    19. Equal volumes of three acid solutions of pH 3, 4 and 5 are mixed in a ...

      Text Solution

      |

    20. The dissociation equilibrium of a gas AB, can be represented as The d...

      Text Solution

      |