A particle moves in the XY-plane according to the law `x = kt, y = kt (1- alphat)`, where k and `alpha` are positive constants and t is time. The trajectory of the particle is

Options

A. `y = kx`
B. `y = x - (alpha x^(2))/(k)`
C. `y =- (ax^(2))/(k)`
D. `y = alpha x`

Answer

B

Explanation

`x = kt, t = (x)/(k)`
Now, `y = k ((x)/(k)) (1-alpha.(x)/(k))` or `y = x - (alpha x^(2))/(k)`