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A particle moves in the XY-plane accordi...

A particle moves in the XY-plane according to the law `x = kt, y = kt (1- alphat)`, where k and `alpha` are positive constants and t is time. The trajectory of the particle is

A

`y = kx`

B

`y = x - (alpha x^(2))/(k)`

C

`y =- (ax^(2))/(k)`

D

`y = alpha x`

Text Solution

Verified by Experts

The correct Answer is:
B
`x = kt, t = (x)/(k)`
Now, `y = k ((x)/(k)) (1-alpha.(x)/(k))` or `y = x - (alpha x^(2))/(k)`
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