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At what temperature will the rms speed o...

At what temperature will the rms speed of oxygen molecules become just sufficient for escaping from the Earth's atmsphere? [ Given, mass of oxygen molecule (m) = `2.76xx10^(-26)` kg, Boltzmann's constant `k_(B) = 1.38 xx 10^(-23) Jcdot K^(-1)` ]

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At what temperature will the average velocity of oxygen molecules be sufficient to escape from the earth. Given mass of oxygen molecule = 5.34 xx 10^(-26) kg . Boltzmann constant, k = 1.38 xx 10^(-23) J "molecule"^(-1) K^(-1) . Escape velocity of earth = 11.0 km s^(-1) .

At what temperature , will the rms speed of oxygen molecules be sufficient for escaping from the earth ? Taken m = 2.76 xx 10^(-26) kg, k = 1.38 xx 10^(-23) J//K and v_(e) = 11.2 km//s .

Knowledge Check

  • At what temperature will the rms speed of oxygen molecules becomes just sufficient for escaping from the Earth's atmosphere ?(Given : Mass of oxygen molecule (m) = 2.76 xx 10^(-26) kg. Boltzmann's constant K_B= 1.38 xx 10^(-23) JK^(-1))

    A
    ` 5.016 xx 10^(4)K`
    B
    ` 8.360 xx 10^(4)K`
    C
    ` 2.508 xx 10^(4)K`
    D
    ` 1.254 xx 10^(4)K`

  • At what temperature the effective speed of gaseous H_2 molecules is equal to that of oxygen molecules at 320 K?

    A
    `20 K`
    B
    `50 K`
    C
    `40 K`
    D
    `30 K`

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    Find the temperature T, At which the r.m.s. speed of oxygen molecules equals to escape velocity (ve) on earth. If the atmosphere contains 4.14 xx 10^16 kg of oxygen, The value of T is T= ..... xx 10^46 K (Boltzmann's constant k_B = 1.38 xx 10^(-23) JK^(-1) )

    At what temperature the kinetic energy of a molecule will be equal to 2.8 xx 10^(-20) J ? Boltzmann constant (k_(B)) = 1.4 xx 10^(-23) J "molecule"^(-1)K^(-1)

    At what temperature, hydrogen molecules will escape from the earth's surface ? (Take, radius of earth R_(e)=6.4xx10^(6)m , mass of hydrogen molecule m=0.34 xx 10^(-26) kg, Boltzmann constant k=1.38xx10^(-23)JK^(-1) and acceleration due to gravity = 9.8 xx ms^(-2) ) also take rms speed of gas as v_(rms) = sqrt((3kT)/(m)) .

    At what temperature the root mean square velocity is equal to escape velocity from the surface of earth for hydrogen and for oxygen ? Given radius of earth = 6.4 xx 10^(6) m , g = 9.8 ms^(-2) . Boltzmann constant = 1.38 xx 10^(-23) J "molecule"^(-1) .

    The diameter of a gas molecule is 2.4 xx 10^(-10) m . Calculate the mean free path at NTP. Given Boltzmann constant k = 1.38 xx 10^(-23) J molecule^(-1) K^(-1) .

    What is the de-Broglie wavelength of nitrogen molecule in air at 300K ? Assume that the molecule is moving with the root mean square speed fo molecules at this temperature. (Atomic mass of nitrogen =14.0076U ) Plank's constant= 6.63xx10^(-34)Js , Boltzmann constant =1.38xx10^(-23)JK^(-1)

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