A body of mass m= 20 g is attached to an...

A body of mass m= 20 g is attached to an elastic spring of length L=50 cm and spring constant k=2 `Nm^(-1)`. The syste is revolved in a horizontal plan with a frequency v=30 rev/min. Find the radius of the circular motion and the tension in the spring .

`0.55 m, 0.1 1N`

`0.5 m, 0.52 N`

`0.55 m, 0.1 N`

`0.9 m, 0.2 N`

Text Solution

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(c) Angular velocity `omega=2pir=2pixx(30)/(60)=pi rad//s` For an elastic spring force `F=kx.` Where x is the extension
Radius of circular motion `r=L+x`
Centripetal force `=mromega^(2)=F`
`rArr" " M(L+x)omega^(2)=kx`
`rArr" " x=(mLomega^(2))/(k-momega^(2))=(0.02xx0.5xx(3.14)^(2))/(2-0.02xx(3.14)^(2))`
Radius of the circular motion (r) `=L+x=0.5+0.05=0.55 M`
Tension in the spring `T=kx =2xx0.05=0.1 N`

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A body of mass m=20g is attached to an elastic spring of length L=50 cm and spring constant k=2Nm^(-1) . The system is revolved in a horizontal plane with a frequency v=30 rev/ min. Find the radius of the circular motion and the tension in the spring.

0.25 m, 0.1 N

0.5 m, 0.52 N

0.55 m 0.1 N

0.9 m, 0.2 N

A block of mass 'm' is attached to a spring in natural length of spring constant 'k' . The other end A of the spring is moved with a constat velocity v away from the block . Find the maximum extension in the spring.

`(1)/(4)sqrt((mv^(2))/(k))`

`sqrt((mv^(2))/(k))`

`(1)/(2)sqrt((mv^(2))/(k))`

`2sqrt((mv^(2))/(k))`

When a 20 g mass hangs attached to one end of a light spring of length 10 cm, the spring stretches by 2 cm. The mass is pulled down until the total length of the spring is 14 cm. The elastic energy, (in Joule) stored in the spring is :

`4xx10^(-2)`

`4xx10^(-3)`

`8xx10^(-2)`

`8xx10^(-3)`