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Starting with the same initial condition...

Starting with the same initial conditions, an ideal gas expands from volume `V_1` to `V_2` in three different ways, the work done by the gas is `W_1` if the process is purely isothermal, `W_2` if purely isobaric and `W_3` if purely adiabatic, then

A

`W_(2)gtW_(1)gtW_(3)`

B

`W_(2)gtW_(3)gtW_(1)`

C

`W_(1)gtW_(2)gtW_(3)`

D

`W_(1)gtW_(3)gtW_(2)`

Text Solution

Verified by Experts

The correct Answer is:
a


It is clear from the graph that on the basis of area under p-V curve for different processes `W_(2)gtW_(1)gtW_(3)`.
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Knowledge Check

  • Starting with the same initial condition, an ideal gas expands from volume V_(1)" to "V_(2) in three different ways. The work done by the gas is W_(1) if the process is isothermal W_(2) if isobaric and W_(1) if adibatic, then :

    A
    `W_(2) gt W_(1) gt W_(3)`
    B
    `W_(2) gt W_(3) gt W_(1)`
    C
    `W_(1) gt W_(2) gt W_(3)`
    D
    `W_(1) gt W_(3) gt W_(2)`
  • With same initial conditions , an ideal gas expands from volume V_(1)" to "V_(2) in three different ways . The work done by the gas is W_(1) if the process is isothermal , W_(2) if isobaric and W_(3) if adiabatic , then

    A
    `W_(2)gtW_(1)gtW_(3)`
    B
    `W_(2)gtW_(3)gtW_(1)`
    C
    `W_(1)gtW_(2)gtW_(3)`
    D
    `W_(1)gtW_(3)gtW_(2)`
  • Starting with the same initial conditions, an ideal gas expands from volume V_(1) to V_(2) . The amount of work done by the gas is greatest when the expansion is

    A
    isothermal
    B
    isobaric
    C
    adiabatic
    D
    equal in all cases
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