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During an isothermal expansion of an ide...

During an isothermal expansion of an ideal gas

A

Its internal energy decreases

B

Its internal energy does not change

C

the work done by the gas is equal to the quantity of heat absorbed by it.

D

both b and c are correct

Text Solution

Verified by Experts

The correct Answer is:
d
In isothermal process, temperautre remains constant
`because DeltaU=nC_(v)DeltaT=0 (because DeltaT=0)`
According to the first law of thermodynamics.
`DeltaH=DeltaU+DeltaW`
`therefore DeltaH=DeltaW (because DeltaU=0)`
Hence, (d) is correct.
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Knowledge Check

  • In an isothermal expansion of an ideal gas

    A
    `P=0`
    B
    `Delta V=0`
    C
    `Delta U =0`
    D
    `W=0`

  • In an isothermal expansion of an ideal gas

    A
    q = 0
    B
    `DeltaV=0`
    C
    W=0
    D
    `DeltaU=0`

  • During the isothermal expansion of an ideal gas:

    A
    The internal energy remains unaffacted
    B
    The temperature remains constant
    C
    The enthalpy remains unaffected
    D
    the enthalpy becomes zero

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