Only 1//8th of the original amount of a ...

Only `1//8th` of the original amount of a radioactive element remains after 96 min. The value of `t_(1//2)` of this element is

12.0 min

32.0 min

24.0 min

48.0 min

Text Solution

Verified by Experts

The correct Answer is:

Given that, `N_(0) = 1, N = (1)/(8), t = 96` min
We know that, `N = N_(0)((1)/(2))^((t)/(t(1//2))) or (1)/(8) = ((1)/(2))^((96)/(t_(1//2)))`
or `((1)/(2))^(3) = ((1)/(2))^((96)/(t_(1//2))) or (96)/(t_(1//2)) = (96)/(3) = 32` min

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After two hours 1//6 th of the initial amount of a certain radioactive isotope remains undecayed. The half life of the isotope is :

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A radioactive isotope decays at such a rate that after 96 min, only 1//8th of the original amount remains. The value of t_(1//2) of this nuclide is a. 12 min b. 32 min c. 24 min d. 48 min

a. 12 min

b. 32 min

c. 24 min

d. 48 min

The half life of 1 gm of a radioactive element of atomic weight M is T. The half life of M gm of the same element will be

`T/M`

`(T M)/2`