The rate constant of a first order reaction is `2.0 xx 10^(-5)s^(-1)` and the initial concentration is 0.10 mol `L^(-1)`. The initial rate is

Options

A. `2.0 xx 10^(-6)"mol " L^(-1)s^(-1)`
B. `1.0 xx 10^(-6)"mol " L^(-1)s^(-1)`
C. `1.5 xx 10^(-6)"mol " L^(-1)s^(-1)`
D. `0.5 xx 10^(-6)"mol " L^(-1)s^(-1)`

Answer

A

Explanation

Rate `((dx)/(dt))` = Rate constant (k) `xx` Concentration
`=2.0xx10^(-5)s^(-1)xx0.10" mol "L^(-1)`
`=2.0 xx 10^(-6)" mol "L^(-1)s^(-1)`