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The rate constant of a first order react...

The rate constant of a first order reaction is `2.0 xx 10^(-5)s^(-1)` and the initial concentration is 0.10 mol `L^(-1)`. The initial rate is

A

`2.0 xx 10^(-6)"mol " L^(-1)s^(-1)`

B

`1.0 xx 10^(-6)"mol " L^(-1)s^(-1)`

C

`1.5 xx 10^(-6)"mol " L^(-1)s^(-1)`

D

`0.5 xx 10^(-6)"mol " L^(-1)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Rate `((dx)/(dt))` = Rate constant (k) `xx` Concentration
`=2.0xx10^(-5)s^(-1)xx0.10" mol "L^(-1)`
`=2.0 xx 10^(-6)" mol "L^(-1)s^(-1)`
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