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Following is the graph between log T(50...

Following is the graph between log `T_(50)` and log a (a = initial concentration) for a given reaction at `27^(@)C`.

Hence, order is

A

1

B

2

C

3

D

0

Text Solution

Verified by Experts

The correct Answer is:
D
`t_(1//2)prop((1)/(a))^(n-1)" or "t_(1//2)=k(a)^(1-n)`
`logt_(1//2)=logk+(1-n)loga`
(It represents straight line equation, y = c + mx)
Slope `=(1-n)=tan45^(@)=1`
`(1-n)=1implies n=0`
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