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Two insulated charged copper spheres A a...

Two insulated charged copper spheres A and B have their centres separated by a distance of 0.5 m. The charge on each spheres is `6.5xx10^(-7)C`. A third sphere c of identifical shape and size is brought in contanct with A and them brought in contact with B and finally removed. What is the new force between A and B?

Text Solution

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Initial charge on A an B `q_(A)=q_(B)=6.5xx10^(-7)C`
When an uncharged conductor C is brought in contact with A, then charge on A and C will be `3.25xx10^(-7)C`. When `C` is brought in contanct with B
Charge on C and B will be `(3.25xx10^(-7)+6.50xx10^(-7))/2=4.875xx10^(-7)C`
The force of repulsion betwen `3.25xx10^(-7)C` (on A) and
`4.875xx10^(-7)C` (on C)`=(9xx10^(9)xx3.25xx10^(-7)xx4.875xx10^(-7))/((0.5)^(2))=5.7xx10^(-3)N`
The new force between A and B is `5.7xx10^(-3)N`
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a. Two insulated charged copper spheres A and B have their centres separated by a distance o 0.5 m. What is the mutual force of electrostatic repulsion if the charge on each is 6.5xx10^(-7)C ? Assume that the radii of A and B are negligible compared to the distance fof separation. b. What is the fore of repulsion if each sphere is charged double the above amount and the distance between them is halved?

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Knowledge Check

  • Two spherical conductors B and C having equal radii and carrying equal charges on them repel each other with a force F when kept apart at some distance . A third ssherical conductor having same radius as that of B but uncharged is brought in contact with B , then brought in contact with C and finally removed away from both . The new force of repulsion between B and C is :

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    B
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    `- 16 C` is at higher potential
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    C
    It cannot be said
    D
    `-5C` is at higher potential

  • Among identical spheres A and B having charges as – 5 and - 16 C

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