Two coils wound on the same iron rod so that the flux generated by one also passes through the other. The primary has 100 turns and the secondary has 200 turns. When a current of 2A flows through the primary, the flux in it is `2.5 xx 10^(-4)` Wb. Determine the value of mutual inductance (M) between the coils.

Explanation

`|e_s|=N_s(dPhi_s)/(dt) and |e_s|=(MdI_p)/(dt)`
`therefore (N_sdPhi_s)/(dt)=(MdI_p)/(dt)`
i.e., `M=(N_sdPhi_s)/(dI_p) "Here" N_s =200 ,dPhi_s 2.5xx10^(-4)-0=2.5xx10^(4) wb`
`dI_p=2-0=2A`
`therefore M=(200xx2.5xx10^(-4))/2=2.5xx10^(-2)H.`