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Two coils wound on the same iron rod so ...

Two coils wound on the same iron rod so that the flux generated by one also passes through the other. The primary has 100 turns and the secondary has 200 turns. When a current of 2A flows through the primary, the flux in it is `2.5 xx 10^(-4)` Wb. Determine the value of mutual inductance (M) between the coils.

Text Solution

Verified by Experts

`|e_s|=N_s(dPhi_s)/(dt) and |e_s|=(MdI_p)/(dt)`
`therefore (N_sdPhi_s)/(dt)=(MdI_p)/(dt)`
i.e., `M=(N_sdPhi_s)/(dI_p) "Here" N_s =200 ,dPhi_s 2.5xx10^(-4)-0=2.5xx10^(4) wb`
`dI_p=2-0=2A`
`therefore M=(200xx2.5xx10^(-4))/2=2.5xx10^(-2)H.`
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Knowledge Check

  • A sotenoid has a mean diameter of 0.05 m and length 2m. It has four layers of 1000 turns each. What is flux density at its centre, when a current of 2.5 A flows through it :

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