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Find the equation of the hyperbola whose...

Find the equation of the hyperbola whose foci are `(0,pm12)` and the length of the lectus rectum is 36 units.

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Find the equation of the hyperbola where foci are (0,+-12) and the length of the latus rectum is 36 .

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Knowledge Check

  • The equation of the hyperbol whose foci are (-2,0) and (2,0) and eccentricity is 2 is given by :

    A
    `x^2-3y^2=3`
    B
    `3x^2-y^2=3`
    C
    `-x^2+3y^2=3`
    D
    `-3x^2+y^2=3`

  • The equation to the ellipse whose foci are (pm2,0) and eccentricity (1)/(2) is :

    A
    `(x^(2))/(12)+(y^(2))/(16)=1`
    B
    `(x^(2))/(16)+(y^(2))/(12)=1`
    C
    `(x^(2))/(16)+(y^(2))/(8)=1`
    D
    None of these

    • Similar Questions

    Explore conceptually related problems

    Find the equation to the hyperbola whose foci, are (6,4) and (-4,4) and eccentricity is 2.

    Find the equation of the ellipse whose foci are at (pm5, 0) and 5x=36 as on of its directrices.

    Find the equation of the ellipse whose foci are (2,3),(-2,3) and whose semi-minor axes is sqrt5 .

    Find the equations of the hyperbola satisfying the given conditions. Foci (+-4,0) , the latus rectum is of length 12 .

    Find the equation of the hyperbola with foci (0,+-3) and vertices (0,+-(sqrt(11))/(2))

    Find the foci of the hyperbola 9x^2-4y^2=36 .

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