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SUBHASH PUBLICATION-TRIGONOMETRY-Prove the following
- cos theta . Cosec theta = cot theta
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- (1-sin(2)A)(1+tan^(2)A)=1
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- (sin theta)/(cosec theta)+(cos theta)/(sec theta)=1
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- tan A . Sin A+ cos A=secA
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- tan A +cotA =secA.cosecA
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- sqrt((1-sinA)/(1+sinA))=secA-tanA
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- cos^(4)A-sin^(4)A=2cos^(2)A-1
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- sin^(6)theta+cos^(6)theta=1-3sin^(2)thetacos^(2)theta
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- (1-cos theta)/(sin theta)=(sin theta)/(1+cos theta)
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- (sin^(2) theta)/(1-cos theta)-(cos^(2) theta)/(1-sin theta)=cos theta-...
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- If x=r cos theta, y=r sin theta Prove that x^(2)+y^(2)=r^(2)
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- (sin x - sin 3x)/(sin^(2)x-cos^(2)x)=2sinx
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- (cos 4x+cos3x+cos2x)/(sin 4x+sin3x+sin2x)=cot3x
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- cot x cot 2x-cot 2x cot3x-cot3x cotx=1
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- tan4x=(4tan x(1-tan^(2)x))/(1-6tan^(2)x+tan^(4)x)
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- Prove that : tan 3x=(3tanx-tan^(3)x)/(1-3tan^(2)x)
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- Prove that: (tan theta)/(1-cot theta)+(cot theta)/(1-tan theta)=1+sec ...
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- (tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos the...
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- If 2 sin^(2) theta +5 cos theta=4, Prove that cos theta=1//2
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- If sec theta=13//5 and theta is acute find (2 sin theta-3 cos theta)/(...
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