S-1 : [Cr(NH(3))(6)]^(3+) is a inner orb...

S-1 : `[Cr(NH_(3))_(6)]^(3+)` is a inner orbital complex with
S-2: The complex formed by joining the CN ligands to `Fe^(3+)` ion has theoretical value fo 'spin only' magnetic moment equal to 1.73 B.M.
S-3: `Na_(2)S+Na_(2)[Fe(CN)_(5)NO]rarrNa_(4)[Fe(CN)_(5)NOS],` In reactan and product the oxidation states of iron are same

F T F

T T F

T T T

F F F

Verified by Experts

(C), All statements are correct.
`(S_(1)) NH_(3)` is strong field ligand so,
`[Cr(NH_(3))_(6)]^(3+)`:

There are three unpaired electrons
`(S_(2))`

`CFSE =-4 xx 3=-1.2 Delta_(0)`
`(S_(3))` CN-strong field ligand and pair up electrons.
`[Fe(CN)_(6)]^(3-):`

`[Fe^(II)(CN)_(5)NO^(+)]^(2-)` :

`[Fe^(II)(CN)_(5)NO^(+)]^(2-) rarr [Fe^(II)(CN)_(5)NOS]^(4-)`
Hence , both reactant and product has same oxidation state of iron i.e. +2

Consider the following statements : statement-1: [Cr(NH_(3))_(6)]^(3+)]^(3+) is an inner orbital complex with crystal field stabilization energy complex with crystal field stabilization energy equal to -1.2 Delta_(0) . Statement -2: The complex formed by joining the CN^(-) ligands to Fe^(3+) ion has theoretical value of 'spin only' magnetic moment equal to 1.73 BM. Statement-3: Na_(2)S+Na_(2) [Fe(CN)_(5)NO] to Na_(4)[Fe(CN)_(5)NOS] , In reactant and product the oxidation states of iron are same and arrange in the order of true/false.

FTF

TTF

TTT

FFF

2, 1

2, 2

2, 3

3, 3

`2,1`

`2,2`

`2,3`

`3,3`