S-1 : `[Cr(NH_(3))_(6)]^(3+)` is a inner orbital complex with
S-2: The complex formed by joining the CN ligands to `Fe^(3+)` ion has theoretical value fo 'spin only' magnetic moment equal to 1.73 B.M.
S-3: `Na_(2)S+Na_(2)[Fe(CN)_(5)NO]rarrNa_(4)[Fe(CN)_(5)NOS],` In reactan and product the oxidation states of iron are same

Options

A. F T F
B. T T F
C. T T T
D. F F F

Explanation

(C), All statements are correct.
`(S_(1)) NH_(3)` is strong field ligand so,
`[Cr(NH_(3))_(6)]^(3+)`:

There are three unpaired electrons
`(S_(2))`

`CFSE =-4 xx 3=-1.2 Delta_(0)`
`(S_(3))` CN-strong field ligand and pair up electrons.
`[Fe(CN)_(6)]^(3-):`

`[Fe^(II)(CN)_(5)NO^(+)]^(2-)` :

`[Fe^(II)(CN)_(5)NO^(+)]^(2-) rarr [Fe^(II)(CN)_(5)NOS]^(4-)`
Hence , both reactant and product has same oxidation state of iron i.e. +2