Match the complexes listed in column-I with characteristic (s)/type of hybridisation olisted in column-II.

Explanation

(A-p.u) , (B-s),(C-s,t),(D-y), (E-q,r).
(A) `Co^(3+) rarr3d^(6)`

bidentate ligands and thus from chelate.
(B) `Co^(3+) rarr3d^(6)`

`F^(-)` weak ligand
(C ) So oxidation state of Cr is (I) and `Cr^(+)` has `d^(5)` configuration. Hence hydridisation is `d^(2)sp^(3)`as two empy d-orbitals are available with strong field ligands `CN^(-)` and `VH_(3)` complex is paramagnetic
(D) `Co^(3+),3d^(6)` configuratiion has greater CFSE. With strong field ligands `NH_(3)` pairing of electrons takes place and thus hybridisation is `d^(2)sp^(3)` and diamagnetic
(E) `Mn^(3+)rarr`

therefore , `mu=sqrt(2(2+))=2.84B.M.`