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Match the complexes listed in column-I w...

Match the complexes listed in column-I with characteristic (s)/type of hybridisation olisted in column-II.

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(A-p.u) , (B-s),(C-s,t),(D-y), (E-q,r).
(A) `Co^(3+) rarr3d^(6)`

bidentate ligands and thus from chelate.
(B) `Co^(3+) rarr3d^(6)`

`F^(-)` weak ligand
(C ) So oxidation state of Cr is (I) and `Cr^(+)` has `d^(5)` configuration. Hence hydridisation is `d^(2)sp^(3)`as two empy d-orbitals are available with strong field ligands `CN^(-)` and `VH_(3)` complex is paramagnetic
(D) `Co^(3+),3d^(6)` configuratiion has greater CFSE. With strong field ligands `NH_(3)` pairing of electrons takes place and thus hybridisation is `d^(2)sp^(3)` and diamagnetic
(E) `Mn^(3+)rarr`

therefore , `mu=sqrt(2(2+))=2.84B.M.`
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Knowledge Check

  • Match the complexed listed column -I with type of hybridisation listed in column -II and select the correct answer using the code given below the lists : {:(,"Column"-I,,"Column"-II,),((a),[AuF_(4)]^(-),,(p)" "dsp^(2)"hybridisation",),((b),[Cu(CN)_(4)]^(3-),,(q)" "sp^(3)"hybridisation",),((c ),[Co(NH_(3))_(6)]^(3+),,(r)" "sp^(3)d^(2)"hybridisation",),((d),[Fe(H_(2)O)_(5)NO]^(2+),,(s)" "d^(2)sp^(3)"hybridisation",):}

    A
    `{:(,"(a)","(b)","(c)","(d)"),(,p,q,s,r):}`
    B
    `{:(,"(a)","(b)","(c)","(d)"),(,p,s,q,r):}`
    C
    `{:(,"(a)","(b)","(c)","(d)"),(,q,p,r,s):}`
    D
    `{:(,"(a)","(b)","(c)","(d)"),(,s,q,p,r):}`

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