Home
Class 12
CHEMISTRY
In copper turnings test, pieces of coppe...

In copper turnings test, pieces of copper is added to a nitrate salt and heated with conc. `H_(2)SO_(4)` .In this reaction copper acts as

A

oxidising agent

B

dehydrating agent

C

reducing agent

D

bleaching agent

Text Solution

AI Generated Solution

The correct Answer is:
To answer the question regarding the role of copper in the copper turnings test when heated with concentrated sulfuric acid and a nitrate salt, we can break down the explanation into several steps: ### Step-by-Step Solution: 1. **Understanding the Copper Turnings Test**: - The copper turnings test is used to identify the presence of nitrate ions in a solution. This is done by adding copper turnings to a nitrate salt and heating it with concentrated sulfuric acid. 2. **Reaction Setup**: - When copper turnings (Cu) are added to a nitrate salt (for example, sodium nitrate, NaNO3) and heated with concentrated sulfuric acid (H2SO4), a chemical reaction occurs. 3. **Chemical Reaction**: - The concentrated sulfuric acid reacts with the nitrate salt to produce nitric acid (HNO3) and sodium bisulfate (NaHSO4): \[ \text{NaNO}_3 + \text{H}_2\text{SO}_4 \rightarrow \text{NaHSO}_4 + \text{HNO}_3 \] - The nitric acid then reacts with copper: \[ \text{Cu} + 4 \text{HNO}_3 \rightarrow \text{Cu(NO}_3\text{)}_2 + 2 \text{NO}_2 + 2 \text{H}_2\text{O} \] 4. **Oxidation State Changes**: - In this reaction, the oxidation state of copper changes from 0 (in elemental copper) to +2 (in copper(II) nitrate). This indicates that copper is losing electrons. 5. **Identifying the Role of Copper**: - Since copper is losing electrons during the reaction, it is undergoing oxidation. In chemical terms, a substance that loses electrons is known as a reducing agent because it reduces another species (in this case, the nitrate ion) by donating electrons. 6. **Conclusion**: - Therefore, in the copper turnings test, copper acts as a **reducing agent**. ### Final Answer: In the copper turnings test, copper acts as a **reducing agent**. ---

To answer the question regarding the role of copper in the copper turnings test when heated with concentrated sulfuric acid and a nitrate salt, we can break down the explanation into several steps: ### Step-by-Step Solution: 1. **Understanding the Copper Turnings Test**: - The copper turnings test is used to identify the presence of nitrate ions in a solution. This is done by adding copper turnings to a nitrate salt and heating it with concentrated sulfuric acid. 2. **Reaction Setup**: ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • QUALITATIVE ANALYSIS

    NARAYNA|Exercise Level -II (H.W.)|40 Videos
  • QUALITATIVE ANALYSIS

    NARAYNA|Exercise LEVEL-V|32 Videos
  • QUALITATIVE ANALYSIS

    NARAYNA|Exercise Passage -I|3 Videos
  • PRACTICAL ORGANIC CHEMISTRY

    NARAYNA|Exercise SUBJECTIVE_TYPE|1 Videos
  • SOLID STATES

    NARAYNA|Exercise EXERCISE-4|18 Videos

Similar Questions

Explore conceptually related problems

What happens when a piece of copper is added to a solution of silver nitrate ?

A salt is heated with dilute H_2 SO_4 and then with conc. H_2 SO_4 . No reaction takes place. It may be

Knowledge Check

  • When the nitrate is heated with conc. H_(2)SO_(4) , gas evolved is

    A
    Brown fumes of `NO_(2)`
    B
    Brown fumes of `Br_(2)`
    C
    Violet fumes of `I_(2)`
    D
    White fumes of NO
  • A salt , which on heating with conc. H_(2)SO_(4) gives violet vapour is

    A
    Iodide
    B
    Nitrate
    C
    Sulphate
    D
    Bromide
  • A salt, which on heating with conc. H_(2)SO_(4) gives violet vapour is

    A
    Iodide
    B
    Nitrate
    C
    Sulphate sulphar
    D
    Bromide//iodide respectively with dil. `HPO_(3)`
  • Similar Questions

    Explore conceptually related problems

    Write the chemical equations of the following reactions : Sodium nitrate is heated with conc. H_(2)SO_(4) .

    Copper reacts with hot conc. H_(2)SO_(4) to give:

    Copper react with conc. H_2SO_4 to gives

    A salt is heated first with dil. H_(2)SO_(4) and then with conc. H_(2)SO_(4) . No reaction takes place. It may be

    7 g copper is heated with conc. H_(2)SO_(4) . The volume of SO_(2) obtained at NTP is