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Position of particle is given by S = t^3...

Position of particle is given by `S = t^3 – 2t^2 + 5t + 4`
(a) Find the position of particle at `t = 1` sec
(b) Find the first derivative of S at `t = 1` sec
(c) Find the second derivative of S `t = 1` sec

Text Solution

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The correct Answer is:
a = 8,b = 4,c = 2, b, `cos theta=(vecF_(1),vecF_(2))/(|vecF_(1)||vecF_(2)|)rArr theta=cos^(-1)((3)/(5sqrt2))` c, `F_(1)cos theta=(vecF_(1),vecF_(2))/(|vecF_(2)|)=(6)/(5)`
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