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Three forces P,Q and R are acting at a p...

Three forces P,Q and R are acting at a point in the plane. The angle between P & Q and Q & R are `150^(@) & 120^(@)` respectively, then for equilibrium, forces P,Q & R are in the ratio

A

`1:2:3`

B

`1:2:sqrt(3)`

C

`3:2:1`

D

`sqrt(3) : 2: 1`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • Three forces P, Q, R are acting at a point in a plane. The angle between P and Q and Q and R are 150^(@) and 120^(@) respectively, then for equilibrium, forces P, Q, R are in the ratio

    A
    `1:2:3`
    B
    `1:2:3^(1//2)`
    C
    `3:2:1`
    D
    `3^(1//2):2:1`

  • Three forces P, Q and R are acting on a particel in the plane, the angle between P and Q and that between Q and R are 150^(@) and 120^(@) respectively. Then for equilibrium, forces P, Q and R are in the ratio

    A
    `1:2:3`
    B
    `1:2:sqrt(3)`
    C
    `3:2:1`
    D
    `sqrt(3):2:1`

  • Given that P 12, Q = 5 and R = 13 also P+Q=R, then the angle between P and Q will be

    A
    `pi`
    B
    `(pi)/(2)`
    C
    zero
    D
    `(pi)/(4)`

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