Home
Class 12
CHEMISTRY
Consider the following E^(@) values: E(L...

Consider the following `E^(@)` values: `E_(Li^(+)|Li)^(@)=-3.05V, E_(Cu^(2+)|Cu)^(@)=+0.34V`
Under similar conditions, the potential for the reaction `Cu+2Li^(+)rarrCu^(2+)+2Li`, is

A

`-3.39V`

B

`+3.39V`

C

`-2.69V`

D

`+2.69V`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • NEET MOCK TEST 20

    NTA MOCK TESTS|Exercise CHEMISTRY|45 Videos
  • NEET MOCK TEST 3

    NTA MOCK TESTS|Exercise CHEMISTRY|45 Videos

Similar Questions

Explore conceptually related problems

If E_(Cu^(2+)|Cu)^(@) = 0.34V and E_(Cu^(2+)|Cu^(+))^(@)= 0.15 V then the value for disproportion for Cu^(+) is :

If for the half cell reaction E^(@) value are given Cu^(2+)+e^(-)rarrCu^(+),E^(@)=0.15V Cu^(2+)+2e^(-)rarrCu^(+),E^(@)=0.34V calculate E^(@) of the half cell reaction Cu^(+)+e^(-)rarrCu

Cu^(2+)+2e^(-)toCu,E^(@)+0.34V Cu^(2+)+e^(-)toCu^(+),E^(@)=+0.15V The equilibrium constant for the reaction Cu+Cu^(2+)to2Cu^(+) at 25^(@)C

Given: (i) Cu^(2+)+2e^(-) rarr Cu, E^(@) = 0.337 V (ii) Cu^(2+)+e^(-) rarr Cu^(+), E^(@) = 0.153 V Electrode potential, E^(@) for the reaction, Cu^(+)+e^(-) rarr Cu , will be

E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=

Which of the following statements is correct? If E_(Cu^(2+)|Cu)^(@)=0.34V "and"E_(H^+|H_2)^(@)=-0.0V

The standard potential E^(@) for the half reactions are as : Zn rarr Zn^(2+) + 2e^(-), E^(@) = 0.76V Cu rarr Cu^(2+) +2e^(-) , E^(@) = -0.34 V The standard cell voltage for the cell reaction is ? Zn +Cu^(2) rarr Zn ^(2+) +Cu