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Consider the following E^(@) values: E(L...

Consider the following `E^(@)` values: `E_(Li^(+)|Li)^(@)=-3.05V, E_(Cu^(2+)|Cu)^(@)=+0.34V`
Under similar conditions, the potential for the reaction `Cu+2Li^(+)rarrCu^(2+)+2Li`, is

A

`-3.39V`

B

`+3.39V`

C

`-2.69V`

D

`+2.69V`

Text Solution

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The correct Answer is:
A
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If for the half cell reaction E^(@) value are given Cu^(2+)+e^(-)rarrCu^(+),E^(@)=0.15V Cu^(2+)+2e^(-)rarrCu^(+),E^(@)=0.34V calculate E^(@) of the half cell reaction Cu^(+)+e^(-)rarrCu

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Knowledge Check

  • If E_(Cu^(2+)|Cu)^(@) = 0.34V and E_(Cu^(2+)|Cu^(+))^(@)= 0.15 V then the value for disproportion for Cu^(+) is :

    A
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    B
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    C
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    D
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    A
    `0.90 V`
    B
    `0.30 V`
    C
    `0.38 V`
    D
    `0.52 V`

  • Cu^(2+)+2e^(-)toCu,E^(@)+0.34V Cu^(2+)+e^(-)toCu^(+),E^(@)=+0.15V The equilibrium constant for the reaction Cu+Cu^(2+)to2Cu^(+) at 25^(@)C

    A
    `2.9xx10^(-8)`
    B
    `3.72xx10^(-7)`
    C
    `2.9xx10^(-5)`
    D
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