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A die is rolled. If the outcome is an ev...

A die is rolled. If the outcome is an even number, what is the probability that it is a prime number ?

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The correct Answer is:
Now, `P(B//A) = (P(A nn B))/(P(A)) = (1)/((6)/((1)/(2))) = (1)/(underset3(cancel6))xx (cancel2)/(1) = 1/3`
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