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A constant couple of 500 Nm turns a whee...

A constant couple of 500 Nm turns a wheel of moment of inertia 100 kg `m^(2)` about an axis through its centre. What will be the angular velocity gained by the body after 2 seconds ?

Text Solution

Verified by Experts

`tau = I alpha`
`tau = (I (omega_(2) - omega_(1)))/(t)`
`omega_(2) - omega_(1) = (tau t)/(I)`
`omega_(2) - omega_(1) = (500 xx 2)/(100) = 5 xx 2 = 10` rad/s
The gain in angular velocity is 10 rad/s.
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