If atomic mass of Argon = 39.9 `mu`, molecular mass of chlorine = `70.9mu` then find the ratio of r.m.s speed of argon atom and chlorine gas molecule.

Explanation

Since `(1)/(2)mv_(mn)^(2) = (3)/(2)k_(B)T` = constant
`v_(mn)prop(1)/(sqrt(m))prop(1)/(sqrt(M))` , M is molar mass / atomic mass.
Hence `((v_(mn))Ar)/((V_(mn))Cl)=sqrt(m_(Cl)/(m_(n)))=sqrt(M_(Cl)/(M_(N)))`
`i.e.((V_(mn))Ar)/((V_(mn))Cl)=sqrt((70.9)/(39.9))=sqrt(1.77)=1.33.`