Home
Class 11
PHYSICS
A force of 100N acts on a body of mass 0...

A force of `100N` acts on a body of mass `0.25kg` for `2s`. Calculate acceleration of the body and its change in momentum.

Text Solution

Verified by Experts

Given, `F=100N`, `m=0.25kg`, `t=2s`
We know that `F=ma`
hence, `a=(F)/(m)=(100)/(0.25)`
change in momentum `=Ft`
`=100xx2=200N`
Promotional Banner

Topper's Solved these Questions

  • LAWS OF MOTION

    SUBHASH PUBLICATION|Exercise Five mark question|4 Videos
  • KINETIC THEORY

    SUBHASH PUBLICATION|Exercise NUMERICALS WITH SOLUTIONS|19 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    SUBHASH PUBLICATION|Exercise NUMERICALS WITH SOLUTIONS|33 Videos

Similar Questions

Explore conceptually related problems

A force of 1 N acts on a body of mass 0.5 kg initially at rest. The ratio of the works done by the force in the first, second and third second is :

The force applied on a body of mass 6 kg. is directly proportional to the acceleration produced in the body. Write an equation to express this observation and draw the graph of the equation.

Calculate the force experienced on a body of mass 5 kg moves with an acceleration of 4 m//s^(2) .

A constant force acts on a body of mass 0.9 kg at rest for 10s. If the body moves a distance of 250m, the magnitude on the force is :

A constant force acts on a body of mass m at rest fort second and then ceases to act. In next 't’ second the body travels a distance 'x'. Magnitude of force is :

A force of 56.6N is sufficient to pull a block of wood of mass 10kg on a horizontal surface. Calculate the angle of friction.