Calculate the rms speed of an ideal gas molecule of mass `2.99xx10^(-25)` kg at 300k.

Explanation

Given, mass of each molecules = `2.99 xx 10^(-26)kg`
temperature T = 300K
We know that, `" "K_(B)=(R)/(N_(A))=(8.314)/(6.023xx10^(23))=1.38xx10^(-23)jk^(-1)`
`therefore " " V_(mn)=sqrt((1.38xx10^(-27)xx300)/(2.99xx10^(-26))=11.77xxsqrt(1000))`
`i.e. " " V_(mn)=372.2ms^(-1).`