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An organic compound contains 4.05% hydro...

An organic compound contains 4.05% hydrogen, 24.26% carbon and 71.67% chlorine. Its milecular mass is 98.96. Find its empirical and molecular formula (Atomic mass of `H=1, C=12, Cl=35.45`)

Text Solution

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Element `" "` % Age `" "` Atomic mass `" "` % ageAto. Mass `" "` Divide by least no `" "` Simdle patio
C `" "` 24.26 `" "` 12 `" "` `24.26/12=2.02` `" "` `2.02/2.02=1` `" "`1
H`" "` 4.05 `" "`1.008`" "4.05/4.008=4.05" "4.05/2.02=2" "2`
Cl`" " 71.67" "35.45" "71.67/35.45=2.02" "2.02/2.02=1" "1`
Emperical formula `=CH_(2)Cl`
`n=("Mol.Mass")/("Emp. formulamass")=98.96/49.42=2`
Mol Formula `=nxx"Emp. formula"=2(CH_(2)Cl)=C_(2)H_(4)Cl_(2)`
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A compound contains 4.07% hydrogen, 24.27% Carbon and 71.65%, Chlorine. Its molar mass is 98.96. Calculate is Empiricla and Molecular formulae.

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  • An organic compound contains C= 40% H= 13.33% and N= 46.67% . Its emperical formula is

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