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The time taken by a particle to slide do...

The time taken by a particle to slide down a smooth inclined plane is double the time it would take in falling down through a height equal to the vertical height of the plane. The inclination of the plane with horizontal is :

A

`30^(@)`

B

`45^(@)`

C

`60^(@)`

D

`90^(@)`

Text Solution

Verified by Experts

The correct Answer is:
A
`((h)/(sin theta)) = (1)/(2) (g t_(1)^(2)) sin theta`
`h = (1)/(2) g t_(2)^(2)`
`t_(1) = 2t_(2)`
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Knowledge Check

  • If the max. range up an inclined plane be one-third of the max. range down the plane then the inclination of the plane to the horizontal is

    A
    `15^(@)`
    B
    `30^(@)`
    C
    `45^(@)`
    D
    `60^(@)`

  • Starting from rest a body slides down a 45^(@) inclined plane in twice the time it takes to slide down the same distance in the absence of friction. The coefficient of the body and the inclined plane is :

    A
    0.75
    B
    0.33
    C
    0.25
    D
    `0.80`

  • The time taken by a block of wood (initially at rest) to slide down a smooth inclined plane 9.8 m long (angle of inclination is 30^(@) ) is

    A
    `(1)/(2)sec`
    B
    `2sec`
    C
    `4sec`
    D
    `1sec`

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