A particle moves so that its coordinates vary with time as x=`alpha sin omegat,y=alpha cos omegat` and `z=bt^(2)`. Find the initial:
(a) position (b) velocity (c) acceleration of the particle.

Explanation

To solve the problem, we will find the initial position, velocity, and acceleration of the particle given its coordinates as functions of time. The coordinates are given as:

- \( x = \alpha \sin(\omega t) \)
- \( y = \alpha \cos(\omega t) \)
- \( z = bt^2 \)

### Step 1: Find the Initial Position
The initial position is found by evaluating the coordinates at \( t = 0 \).
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