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A particle moves so that its coordinates...

A particle moves so that its coordinates vary with time as x=`alpha sin omegat,y=alpha cos omegat` and `z=bt^(2)`. Find the initial:
(a) position (b) velocity (c) acceleration of the particle.

Text Solution

AI Generated Solution

To solve the problem, we will find the initial position, velocity, and acceleration of the particle given its coordinates as functions of time. The coordinates are given as: - \( x = \alpha \sin(\omega t) \) - \( y = \alpha \cos(\omega t) \) - \( z = bt^2 \) ### Step 1: Find the Initial Position The initial position is found by evaluating the coordinates at \( t = 0 \). ...
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Knowledge Check

  • A particle moves so that its position vector varies with time as vec(r )= A cos omegathat(i)+A sin omega t hai(j) . The initial velocity of the particel the particle is

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    D
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    A
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