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An iron sphere weights 10 N and rests in...

An iron sphere weights 10 N and rests in a V- shaped trough whose sides form an angle of `60^(@)` What are the normal forces exerted by the walls on the sphere in cases as shown in?

Text Solution

Verified by Experts

The correct Answer is:
(a) `R_(A) = 10N and R_(B)=0`
(b) `R_(A)=R_(B)=10N`
(c) `R_(A)=20//sqrt(3)N and R_(B)=(10//sqrt(3))N`

`(a)R_(A)=10N=W`
`R_(B)=0`

(b) `R_(A)=R_(B)`
`2R_(A) cos 60^(@)=W`
`R_(A)=W=10N=R_(B)`

(c) `R_(A) cos 60^(@)=R_(B)`
`R_(A) sin 60^(@)=W=10`
`R_(A)=(10xx2)/sqrt(3)=20/sqrt(3)N`
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Knowledge Check

  • An iron sphere weighing 10N rests in a V shaped smooth trough whose sides form an angle of 60^(@) as shown in the Then the reaction forces are .

    A
    `R_(A) =10N` and `R_(B) = 0` in case (i)
    B
    `R_(A) =10N` and `R_(3) =10N` in case (ii)
    C
    `R_(A) = (20)/(sqrt3)N` and `R_(B) = (10)/(sqrt3)N` in case (iii)
    D
    `R_(A) =10N` and `R_(B) =10N` in all the `3` cases
  • A small sphere D of mass and radius rols without slipping inside a large fixed hemispherical radius R( gt gt r) as shown in figure. If the sphere starts from rest at the top point of the hemisphere normal force exerted by the small sphere on the hemisphere when its is at the bottom B of the hemisphere. .

    A
    `(10)/(7) mg`
    B
    `(17)/(7) mg`
    C
    `(5)/(7) mg`
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    `(7)/(5) mg`
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    A
    `N_(1)gtN_(2)`
    B
    `N_(1)ltN_(2)`
    C
    `N_(1)=N_(2)`
    D
    `N_(1)` and `N_(2)` would be in the vertical directions
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