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A cricket ball of mass 150 kg is moving ...

A cricket ball of mass 150 kg is moving with a velocity of `12 m//s` and is hit by a bat so that ball is turned back with a velocity of `20 m//s` . The force of the blow acts for 0.01 s on the ball . Find the average force exerted by the bat on the ball.

Text Solution

Verified by Experts

According to given problem, change in momentum of the ball
`Deltap=pf-p i=m(v-u)=150xx10^(-3)[20-(-12)]`
So, by impulse momentum theorem,
`J=Deltap=4.8N-s`
And by time averaged definition of force in case of impulse,
`F_(av)=J/(Deltat)=(Deltap)/(Deltat)=(4.80)/(0.01)=480N`
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Knowledge Check

  • A cricket ball of mass 150g is moving with a velocity of 12 m/s and is hit by a bat so that the ball is turned back with a velocity ishit by a bat so that the ball is turned back with a velocity of 20 m/s. The force of blow acts for 0.01 s on the ball. What is the averate force exerted by the bat on the ball?

    A
    240N
    B
    300N
    C
    380N
    D
    480N

  • A cricket ball of mass 150 g is moving with a speed of 12ms^(-1) and is hit by a bat so that the ball is turned back with velocity of 20ms^(-1) if duration of contact between bat and ball is 0.01 s then:

    A
    impulse of force is `4.8` Ns
    B
    average force exerted by bat is 480 N
    C
    retarding of the ball is `3200ms^(-2)`
    D
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  • According to Newton s second law of motion F =ma where F is the force required to produce an acceleration a in a body of mass m If a = 0 then F = 0 no external force is required to move a body uniformly along a straight line If a force F acts on a body for t seconds the effect of the force is given by Impulse =F xx t = change in linear momentum of the body A cricket ball of mass 150g is moving with a velocity of 12m//s and is hit by a bat so that the ball is turned back with a velocity of 20m//s if duration of contact between the ball and the bat is 0.01sec The impulse of the force is .

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