A cricket ball of mass 150 kg is moving with a velocity of `12 m//s` and is hit by a bat so that ball is turned back with a velocity of `20 m//s` . The force of the blow acts for 0.01 s on the ball . Find the average force exerted by the bat on the ball.

Explanation

According to given problem, change in momentum of the ball
`Deltap=pf-p i=m(v-u)=150xx10^(-3)[20-(-12)]`
So, by impulse momentum theorem,
`J=Deltap=4.8N-s`
And by time averaged definition of force in case of impulse,
`F_(av)=J/(Deltat)=(Deltap)/(Deltat)=(4.80)/(0.01)=480N`