Let `S` be the sum, `P` be the product and `R` be the sum of the reciprocals of 3 terms of a G.P. then `P^2R^3: S^3` is equal to
(a)`1:1`

(b) `("common ratio")^n :1`
(c)`("First term")^2("common ratio")^2`
(d) None of these

Explanation

Let the first term and common ratio of a G.P be A and R respectively.

so

we know that,

`S=(AR^(n)−1)/(R-1)`

and product,

`​P=A(AR)(AR^2)(AR^3)........(AR^(n−1))`

`⇒P=A^nR^(1+2+3+........+n−1)`

`=>A^nR^((n(n-1))/2)`

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