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Two intersecting lines lying in plane P(...

Two intersecting lines lying in plane `P_(1)` have equations `(x-1)/(1)=(y-3)/(2)=(z-4)/(3)` and `(x-1)/(2)=(y-3)/(3)=(z-4)/(1).` If the equation of plane `P_(2)` is `7x-5y+z-6=0`, then the distance between planes `P_(1) and P_(2)` is

A

`(11)/(5sqrt3)`

B

`(2)/(sqrt3)`

C

`(1)/(sqrt3)`

D

`(7)/(5sqrt3)`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • The projection of the line (x-1)/(2)=(y+1)/(1)=(z-2)/(3) on a plane P is (x-1)/(1)=(y+1)/(2)=(z-2)/(1) , then the equation of the plane P is

    A
    `5x-8y+11z=35`
    B
    `5x+8y-21z+45=0`
    C
    `5x+8y+11z=35`
    D
    `5x-8y+21z=45`

  • If the line (x-1)/2=(y+3)/1=(z-5)/(-1) is parallel to the plane px + 3y - z + 5 = 0 , then the value of p -

    A
    2
    B
    `-2`
    C
    `1/2`
    D
    `1/3`

  • Equation of a line and a plane are respectively (x+3)/(2)=(y-4)/(3)=(z+5)/(1) and 2x-3y+5z=1. Then

    A
    line lies in the plane
    B
    line is parallel to the plane
    C
    line is perpendicular to the plane
    D
    none of these

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