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Let P(1) : 2x + y + z + 1 = 0 P(2) : 2...

Let `P_(1) : 2x + y + z + 1 = 0`
`P_(2) : 2x - y + z + 3 = 0` and `P_(3) : 2x + 3y + z + 5 = 0` be three planes, then the distance of the line of intersection of planes `P_(1) = 0` and `P_(2) = 0` from the plane `P_(3) = 0` is

A

`3/(sqrt(14))` units

B

`6/(sqrt(14))` units

C

`3/(sqrt(7))` units

D

`6/(sqrt(7))` units

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • Let P_(1)=x+y+z+1=0, P_(2)=x-y+2z+1=0,P_(3)=3x+y+4z+7=0 be three planes. Find the distance of line of intersection of planes P_(1)=0 and P_(2) =0 from the plane P_(3) =0.

    A
    `(2)/sqrt(26)`
    B
    `(4)/sqrt(26)`
    C
    `sqrt((1)/(26))`
    D
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  • P_(1) : x + 3y - z = 0 and P_(2) , y + 2z = 0 are two intersecting planes P_(3) is a plane passing through the point (2,1,-1) and through the line of intersection of P_(1) and P_(2) Equation of P_(3) is

    A
    4x + y - 2z = 10
    B
    x + y - 2z = 3
    C
    x + 9y + 11z = 0
    D
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  • P_(1) : x + 3y - z = 0 and P_(2) : y + 2z = 0 are two intersecting planes P_(3) is a plane passing through the point (2,1,-1) and through the line of intersection of P_(1) and P_(2) __________ is a point on P_(3) .

    A
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    B
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    C
    (-6,-3,3)
    D
    (6,3,-3)

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