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Let P(1) : 2x + y + z + 1 = 0 P(2) : 2...

Let `P_(1) : 2x + y + z + 1 = 0`
`P_(2) : 2x - y + z + 3 = 0` and `P_(3) : 2x + 3y + z + 5 = 0` be three planes, then the distance of the line of intersection of planes `P_(1) = 0` and `P_(2) = 0` from the plane `P_(3) = 0` is

A

`3/(sqrt(14))` units

B

`6/(sqrt(14))` units

C

`3/(sqrt(7))` units

D

`6/(sqrt(7))` units

Text Solution

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The correct Answer is:
B
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