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In the expansion of (1 + x)^(n) (1 + y)^...

In the expansion of `(1 + x)^(n) (1 + y)^(n) (1 + z)^(n)` , the sum of the co-efficients of the terms of degree `r` is

A

`.^(n^(3))C_(r)`

B

`.^(n)C_(r^(3))`

C

`.^(3n)C_(r)`

D

`3.^(2n)C_(r)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the sum of the coefficients of the terms of degree \( r \) in the expansion of \( (1 + x)^{n} (1 + y)^{n} (1 + z)^{n} \), we can follow these steps: ### Step 1: Understand the Expansion The expression \( (1 + x)^{n} (1 + y)^{n} (1 + z)^{n} \) can be expanded using the binomial theorem. Each binomial expansion contributes terms of varying degrees. ### Step 2: Identify the Degree of Terms The degree of a term in the expansion is the sum of the powers of \( x \), \( y \), and \( z \). For example, a term like \( x^a y^b z^c \) has a degree \( a + b + c \). ### Step 3: Count the Coefficients To find the sum of the coefficients of the terms of degree \( r \), we need to consider all combinations of \( x \), \( y \), and \( z \) that add up to \( r \). This can be represented as selecting \( r \) items from three groups (corresponding to \( x \), \( y \), and \( z \)). ### Step 4: Use the Multinomial Theorem The total number of ways to choose \( r \) items from three groups (where each group can contribute from 0 to \( r \)) can be calculated using the multinomial coefficient. Specifically, we can express this as: \[ \sum_{a + b + c = r} \frac{r!}{a! b! c!} \] ### Step 5: Substitute into the Binomial Expansion Since we are dealing with three identical expansions of \( (1 + x)^{n} \), we can rewrite the expression as: \[ (1 + x)^{3n} \] ### Step 6: Find the Coefficient of \( x^r \) The coefficient of \( x^r \) in the expansion of \( (1 + x)^{3n} \) is given by: \[ \binom{3n}{r} \] ### Final Answer Thus, the sum of the coefficients of the terms of degree \( r \) in the expansion of \( (1 + x)^{n} (1 + y)^{n} (1 + z)^{n} \) is: \[ \binom{3n}{r} \]
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Knowledge Check

  • In the expansion of (1+x)^(2)(1+y)^(3)(1+z)^(4)(1+w)^(5) , the sum of the coefficient of the terms of degree 12 is :

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  • Consider the expansion of (1 + x)^(2n+1) The sum of the coefficients of all the terms in the expansion is

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    D
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