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If (4+sqrt(15))^n=I+f,w h r en is an odd...

If `(4+sqrt(15))^n=I+f,w h r en` is an odd natural number, `I` is an integer and `0

A

I is an odd interger

B

I is an even interger

C

`(I+f)(1-f)=1`

D

`1-f=(4-sqrt(5))^(n)`

Text Solution

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The correct Answer is:
A, C, D
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Knowledge Check

  • What is the sum of first 15 odd natural number?

    A
    255
    B
    225
    C
    235
    D
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  • What is the sum of first 15 odd natural numbers?

    A
    255
    B
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    D
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  • If n is a positive integer and (5sqrt(5)+11)^(2n+1)=I+f where I is an integer and 0 lt f lt 1 , then

    A
    I is an even integer
    B
    `(I+f)^(2)` is divisible by `2^(2n+1)`
    C
    I is divisible by 22.
    D
    None

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