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A stationary uniform rod of mass 'm', l...

A stationary uniform rod of mass 'm', length 'l' leans against a smooth vertical wall making an angle `theta` with horizontal floor. Find the normal force & frictional force that is exerted by the floor on the rod ?

Text Solution

Verified by Experts

As the rod is stationary so the linear acceleration and angular acceleration of rod is zero.
i.e., `a_(cm) = 0 , alpha = 0 `
`{:(N_(2)=f),(N_(1)=mg):}}:'a_(am) = 0 `
Torque about any point of the rod should also be zero
`:. alpha = 0 `
`tau_(A) = 0 rArr mg cos theta (l)/(2) + f l sin theta = N_(1) cos theta . l `
` N_(1) cos theta = sin theta f + (mg cos theta)/(2)`
`f = (mg cos theta)/(2 sin theta) = (mg cot theta)/(2)`
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Knowledge Check

  • A rod of mass m is released on smooth horizontal surface making angle theta with horizontal. Then which of the following statement is correct ?

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    B
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    C
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  • A uniform rod AB of mass m and length L rotates about a fixed vertical axis making a constant angle theta with it as shown in figure. The rod is rotated about this axis, so that point B the free end of the rod moves with a uniform speed V in the horizontal plane then the angular momentum of the rod about the axis is:

    A
    `(1)/(2)mVLcostheta`
    B
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  • In the figure, a ladder of mass m is shown leaning against a wall. It is in static equilibrium making an angle theta with the horizontal floor. The coefficient of friction between the wall and the ladder is mu_1 and that between the floor and the ladder is mu_2. the normal reaction of the wall on the ladder is N_1 and that of the floor is N_2. if the ladder is about to slip. than

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    B
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    C
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    D
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