If the abscissae and the ordinates of two point `Aa n dB` be the roots of `x^2+2ax−b^2 `a n d `x^2+2px−q^2=0` respectively, show that the equation of the circle described on `A B` as diameter is `x^2+y^2+2ax+2py−b^2−q^2=0`

Explanation

Given,`x^2+2ax−b^2=0`


Let roots be `x_1`​ & `x_2`​


`x_1​+x_2​=(−b)/a​=−2a`


`x_1​x_2​=c/a​=−b^2`


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