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sin^(2) A cos^(2)B + cos ^(2) A sin^(2) ...

`sin^(2) A cos^(2)B + cos ^(2) A sin^(2) B + sin^(2) A sin^(2) B+ cos^(2) A cos^(2) B=`

A

0

B

1

C

`-1`

D

2

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • (sin^(2)3A)/(sin^(2)A)-(cos^(2) 3A)/(cos^(2)A)=

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    `2(a^(2) + b^(2) )`
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