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In a triangleABC, A :B:C= 3:5:4. Then a+...

In a `triangleABC`, A :B:C= 3:5:4. Then `a+b+csqrt(2)` is equal to

A

2b

B

2c

C

3b

D

3a

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • In Delta ABC , if angle A: angle B: angle C=3:5:4 , then a+b+sqrt(2c) is equal to

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    D
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    2
    B
    16
    C
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    D
    128

  • In triangleABC, a^(2)sin(B-C)=

    A
    `(b^(2)-c^(2))sinA`
    B
    `(c^(2)-b^(2))sinA`
    C
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    D
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