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If twice the square of the diameter of t...

If twice the square of the diameter of the circle is equal to half the sum of the squares of the sides of incribed triangle ABC,then `sin^(2)A+sin^(2)B+sin^(2)C` is equal to

A

2

B

3

C

4

D

1

Text Solution

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A
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Knowledge Check

  • If twice the square on the diameter of a circle is equal to sum of the squares on the sides of the inscribed triangle ABC, then sin^2 A+sin^2 B+sin^2 C is equal to

    A
    2
    B
    3
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    D
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  • If A, B, C are the angles of a triangle then sin^(2)A+sin^(2)B+sin^(2)C-2cosAcosBcosC is equal to

    A
    1
    B
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    C
    3
    D
    4

  • If A, B, C are the angles of a triangle, then sin 2A + sin 2B - sin 2C is equal to

    A
    `4 sin A cos B cos C`
    B
    ` 4 cos A`
    C
    ` 4 sin A cos A`
    D
    `4 cos A cos B sin C`

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