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HgCl(2) on passing H(2)S gives -...

`HgCl_(2)` on passing `H_(2)S` gives -

A

HgS

B

`Hg_(2)S`

C

`Hg + HgS`

D

`HgS + H_(2)S`

Text Solution

Verified by Experts

The correct Answer is:
A
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