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HgCl(2) on passing H(2)S gives -...

`HgCl_(2)` on passing `H_(2)S` gives -

A

HgS

B

`Hg_(2)S`

C

`Hg + HgS`

D

`HgS + H_(2)S`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • A very dilute acidic solution of Cd^(2+) and Ni^(2+) gives only yellow ppt. of CdS on passing H_(2)S , this is due to

    A
    Solubility product `(K_(sp))` of CdS is more than that of NiS
    B
    Solubility product `(K_(sp))` of CdS is less than that of NiS
    C
    `Cd^(2+)` belong to IIB group while `Ni^(2+)` belongs to `IV^(th)` group
    D
    CdS is insoluble in yellow ammonium sulphide (YAS)

  • A very dilute acidic solution of Cd^(2+)&Ni^(2+) gives only yelllwo ppt. of CdS on passing H_(2)S , this is due to:

    A
    solubility product `(K_(sp))` of CdS is more than that of NiS.
    B
    Solubility product `(K_(sp))` of CdS is less than that of NiS.
    C
    `Cd^(2+)` belong to II B group while `Ni^(2+)` belongs to `IV`th group
    D
    CdS is insoluble in yellow ammonium sulphide (YAS).

  • A very dilute acidic solution of Cd^(2+)&Ni^(2+) gives only yelllwo ppt. of CdS on passing H_(2)S , this is due to:

    A
    solubility product `(K_(sp))` of CdS is more than that of NiS.
    B
    Solubility product `(K_(sp))` of CdS is less than that of NiS.
    C
    `Cd^(2+)` belong to II B group while `Ni^(2+)` belongs to `IV`th group
    D
    CdS is insoluble in yellow ammonium sulphide (YAS).

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    Aniline on being heated with CS_(2) in the presence of HgCl_(2) gives-

    Yellow ammonium sulphide is obtained by passing H_(2)S into

    When H_(2)S is passed through Hg_(2)S we get

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