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Calculate the moment of Inertia of a sem...

Calculate the moment of Inertia of a semicircular disc of mass M and radius R about an axis passing through its centre and perpendicular to its plane.

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To calculate the moment of inertia of a semicircular disc of mass \( M \) and radius \( R \) about an axis passing through its center and perpendicular to its plane, we will follow these steps: ### Step 1: Understand the Geometry The semicircular disc can be thought of as half of a full circular disc. The moment of inertia of a full circular disc about an axis perpendicular to its plane and through its center is given by the formula: \[ I_{\text{full}} = \frac{1}{2} M R^2 \] where \( M \) is the mass of the disc and \( R \) is its radius. ...
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Knowledge Check

  • Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is

    A
    `1//2MR^(2)`
    B
    `MR^(2)`
    C
    `1//4MR^(2)`
    D
    `3//4 MR^(2)`
  • The radius of gyration of a disc about its axis passing through its centre and perpendicular to its plane is

    A
    `R//sqrt(2)`
    B
    R/2
    C
    `sqrt(2)` R
    D
    2R
  • Moment of inertia of a uniform quarter disc of radius R and mass M about an axis through its centre of mass and perpendicular to its plane is :

    A
    `(MR^(2))/(2)-M((4R)/(3pi))^(2)`
    B
    `(MR^(2))/(2)-M(sqrt(2)(4R)/(3pi))^(2)`
    C
    `(MR^(2))/(2)+M((4R)/(3pi))^(2)`
    D
    `(MR^(2))/(2)+M(sqrt(2)(4R)/(3pi))^(2)`
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