Home
Class 12
PHYSICS
The M.I. of a disc about its diameter is...

The M.I. of a disc about its diameter is 2 units. Its M.I. about axis through a point on its rim and in the plane of the disc is

A

4 units.

B

6 units

C

8 units

D

10 units

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • ROTATIONAL MOTION

    MOTION|Exercise Exercise - 2|40 Videos
  • ROTATIONAL MOTION

    MOTION|Exercise Exercise - 3 ( Section-A )|46 Videos
  • ROTATIONAL MOTION

    MOTION|Exercise Exercise - 3 ( Section-B )|24 Videos
  • RAY OPTICS

    MOTION|Exercise Exercise-4|38 Videos
  • SEMI CONDUCTOR AND LOGIC GATES

    MOTION|Exercise EXERCISE 3|34 Videos

Similar Questions

Explore conceptually related problems

The M.I. of a uniform disc about a diameter is I. Its M.I. about an axis perpendiçular to its plane and passing through a point on its rim is

The M.L. of a uniform disc about the diameter is 1. Its M.I. about an axis perpendicular to its plane and passing through a point on its rim is

The M.I. of a disc of mass M and radius R, about an axis passing through the centre O and perpendicular to the plane of the disc is (MR^(2))/(2) . If one quarter of the disc is removed, the new moment of inertia of the disc will be

The diagram shows a uniform disc of mass M & radius ' a ', if the moment of inertia of the disc about the axis XY is I , its moment of inertia about an axis through O and perpendicular to the plane of the disc is

M.I. of a thin uniform circular disc about one of the diameters is I. Its M.I. about an axis perpendicular to the plane of disc and passing through its centre is

A disc of radius r is removed from the centre of a disc of mass M and radius R. The M.I. About the axis through the centre and normal to the plane will be:

Moment of inertia of a uniform circular disc about a diameter is I . Its moment of inertia about an axis perpendicular to its plane and passing through a point on its rim will be.

Moment of inertia (M.I.) of four bodies, having same mass and radius, are reported as , I_1 = M.I. of thin circular ring about its diameter. I_2 = M.I. of circular disc about an axis perpendicular to the disc and going through the centre, I_3 = M.I. of solid cylinder about its axis and I_4 = M.I. of solid sphere about its diameter. Then :

MOTION-ROTATIONAL MOTION -Exercise - 1
  1. The M.I. of a disc about its diameter is 2 units. Its M.I. about axis ...

    Text Solution

    |

  2. Which of the following quantity is direction less

    Text Solution

    |

  3. A disc of metal is melted to recast in the form of a solid sphere. The...

    Text Solution

    |

  4. The physical significance of mass translational motion is same as whic...

    Text Solution

    |

  5. Moment of inertia of a body depends upon

    Text Solution

    |

  6. On account of melting of ice at the north pole the moment of inertia o...

    Text Solution

    |

  7. Two spheres of same mass and radius are in contact with each other. If...

    Text Solution

    |

  8. In an arrangement four particles, each of mass 2 gram are situated at ...

    Text Solution

    |

  9. A stone of mass 4kg is whirled in a horizontal circle of radius 1m and...

    Text Solution

    |

  10. The moment of inertia of NaCl molecule with bond length r about an axi...

    Text Solution

    |

  11. The moment of inertia of a body does not depend on

    Text Solution

    |

  12. The moment of inertia of a sphere of radius R about an axis passing th...

    Text Solution

    |

  13. Moment of inertia of a cylindrical shell of mass M, radius R and lengt...

    Text Solution

    |

  14. A solid sphere and hollow sphere of the same material have mass. Then ...

    Text Solution

    |

  15. Two discs have same mass and thickness. Their materials are of densiti...

    Text Solution

    |

  16. A circular disc A of radius r is made from an iron plate of thickness ...

    Text Solution

    |

  17. Three thin uniform rods each of mass M and length L and placed along t...

    Text Solution

    |

  18. Three rings, each of mass P and radius Q are arranged as shown in the ...

    Text Solution

    |

  19. The torque needed to produce an angular acceleration of 18rad/"sec"^2 ...

    Text Solution

    |

  20. The product of moment of inertia (I) and angular acceleration (alpha) ...

    Text Solution

    |