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A particle of mass 0.01 kg having positi...

A particle of mass 0.01 kg having position vector `vecr = ( 10 hati + 6 hatj)` meters is moving with a velocity `5 hati `m/s . Calculate its angular momentum about the origin.

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To calculate the angular momentum of a particle about the origin, we can use the formula: \[ \vec{L} = \vec{r} \times \vec{p} \] where: - \(\vec{L}\) is the angular momentum, ...
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Knowledge Check

  • A partical has the position vector r = hati - 2 hatj + hatk and the linear momentum p = 2 hati - hatj + hatk its angular momentum about the origin is

    A
    `-hati+hatj-3hatk`
    B
    `-hati+hatj+3hatk`
    C
    `hati+hatj+3hatk`
    D
    `hati-hatj-5hatk`

  • The position of a particle is given by vecr = hati + 2hatj - hatk and its linear momentum is given by vecp = 3hati+4 hatj - 2hatk . Then its angular momentum, about the origin is perpendicular to

    A
    yz-plane
    B
    z-axis
    C
    y-axis
    D
    x-axis

  • The displacement of a particle from a point having position vector 2hati + 4hatj to another point having position vector 5hatj + 1hatj is

    A
    3 units
    B
    `3sqrt2` units
    C
    5 units
    D
    ` 5sqrt3`units

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    A particle of mass 2 kg located at the position (hati + hatj)m has velocity 2(hati - hatj + hatk) m//s . Its angualr momentum about Z-axis in kg m^(2)//s is

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